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Sholpan [36]
3 years ago
6

Write an equation of the line in slope intercept form that passes through the given pint and is parallel to the given line (-1,3

) y=2x+2
Mathematics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:


Step-by-step explanation:

Answer:

y = 2x + 5

Step-by-step explanation:

y = mx + b    :    Slope Intercept Form

Our m (slope) does not change, but our b (y-intercept) does.


Step 1: Plug in all numbers except b

y = 2x + b

3 = 2(-1) + b

Solve

5 = b


Step 2: Add slope and intercept into equation

y = 2x + 5

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find the coordinates of the points D ( 4, -4 ) and E ( 5, -5 ) after the transformation ( x; y ) ( x + 3, y -5
postnew [5]

Answer:

second option

Step-by-step explanation:

Given the rule

(x, y ) → (x + 3, y - 5)

This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is

D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )

E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )

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3 years ago
The sum of two numbers is 68 . the smaller number is 12 less than the larger number. what are the numbers?
galben [10]
The larger number is 56 because if you do 68-12=56
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3 years ago
the Millers drove 105 miles on 4 gallons of gas. at this rate, how many miles can they drive on 6 gallons of gas.
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Answer:

157.5 miles with 6 gallons

Step-by-step explanation:

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3 years ago
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Estimate the sum 9/10 + 7/8 A.about 0 B.about 1 C.about 1/2 D. about 2
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The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine
salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

                                              f(x)=\frac{e^{\frac{-x}{1000} }}{1000}

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

              b. P(1000<x<2000) = 0.2325

              c. P(x<1000) = 0.6321

              d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = \int\limits^b_a {P(x)} \, dx

Then, for the electronic component, probability will be:

P(a<x<b) = \int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx

P(a<x<b) = \frac{1000}{1000}.e^{\frac{-x}{1000} }

P(a<x<b) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

a. For a component to last more than 3000 hours:

P(3000<x<∞) = e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = e^{-3}

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}

P(1000<x<2000) = e^{-2}-e^{-1}

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}

P(0<x<1000) = e^{-1}-1

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

0.1 = 1-e^\frac{-x}{1000}

-e^{\frac{-x}{1000} }=-0.9

{\frac{-x}{1000} }=ln0.9

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0
4 years ago
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