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3 years ago

Pls help me, i’ll give brainly

Mathematics

1 answer:

Papessa [141]3 years ago

5 0

Answer/Step-by-step explanation:

First, find the slope (m) of Line L using the points (0, 5) and (2, 1):

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{2 - 0} = \frac{-4}{2} = -2$

Slope (m) = -2

✔️Since the line is parallel bro Line L, it would also have the same slope value of -2.

We can use the slope (m) and a point (a, b) of the line to find its equation using the point-slope formula, y - b = m(x - a).

Substitute (a, b) = (3, 0), and m = -2 into y - b = m(x + a):

Thus,

✅y - 0 = -2(x + 3)

Rewrite equation in slope-intercept form

y = -2(x + 3)

✅y = -2x - 6

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What is the slope of the line that passes through the points (-4,0) and (2,0)

S_A_V [24]

Slope = (y2 - y1) / (x2 - x1)
Slope = (0 - 0) / (2 --4)
Slope = (0) / (6)
Slope = 0

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3 years ago

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6(x-2)= -18 find what x equals

KIM [24]

Answer:

-1

Step-by-step explanation:

x-2 = -3

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answer is negative one

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3 years ago

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This is math, help me with it plz

dangina [55]

Answer: X=136 degrees
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2 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

If KM = 32 units, KL = 3x+6 and LM= 11 units, what is the value of x?

Rus_ich [418]

Answer:

Step-by-step explanation:

|<------------------- 32 units ---------------->|

K-----------------------L-------------------------M

3x + 6 11

KL + LM = KM

3x + 6 + 11 = 32

3x = 32 - 11 - 6

x = 15 / 3

x = 5 units

7 0

3 years ago