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Hitman42 [59]
3 years ago
6

Pls help me, i’ll give brainly

Mathematics
1 answer:
Papessa [141]3 years ago
5 0

Answer/Step-by-step explanation:

First, find the slope (m) of Line L using the points (0, 5) and (2, 1):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{2 - 0} = \frac{-4}{2} = -2

Slope (m) = -2

✔️Since the line is parallel bro Line L, it would also have the same slope value of -2.

We can use the slope (m) and a point (a, b) of the line to find its equation using the point-slope formula, y - b = m(x - a).

Substitute (a, b) = (3, 0), and m = -2 into y - b = m(x + a):

Thus,

✅y - 0 = -2(x + 3)

Rewrite equation in slope-intercept form

y = -2(x + 3)

✅y = -2x - 6

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17 + x =31 <br> i need help
Gelneren [198K]

Answer:

x= 14

Step-by-step explanation:

First (and only) we subtract 17 from both sides :

17 + x - 17 = 31 - 17

x = 31 - 17

x = 14

Hope this helped and have a good day

4 0
2 years ago
Read 2 more answers
HELP ME PLEASE ASAP?!?What is the value of y?
Snezhnost [94]
Answer: y = 57°

Explanation: 180-114 = 66°

A triangle has a total of 180° so 180-66 = 114

114 / 2 = 57° (because angles y and y have the same value)

Hope this helps :)
7 0
3 years ago
Four posters cost $19.20. How many posters can you buy for $48.00?
stich3 [128]
You can buy 8 posters with 48.00 19.20x2=38.40 the leftover change isn’t enough to buy more
8 0
3 years ago
A gold mine is projected to produce $52,000 during its first year of operation, $50,000 the second year, $48,000 the third year,
marshall27 [118]

Answer:

its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

Step-by-step explanation:

Given that;

gold mine is projected to produce $52,000 during its first year

produce $50,000 the second year

produce $48,000 the third year

the mine is expected to produce for 20yrs; i.e n = 20

annual interest rate = 4% = 0.04%

now let P represent the present worth

we determine the present worth ;

Present worth ⇒ Cashflow(Uniform series present worth) - (2000)(uniform gradient present worth)

⇒Cashflow(P | A,i%,n) - (2000)(P | G,i%,n)

= 52000[ ((1+i)ⁿ - 1) / (i(1+i)ⁿ) ] - (2000)[ {((1+i)ⁿ - 1) / (i²(1+i)ⁿ))} - (n/i(1 + i)ⁿ) ]

= 52000[ ((1+0.04)²⁰ - 1) / (0.04(1+0.04)²⁰) ] - (2000)[ {((1+0.04)20 - 1) / ((0.04)²(1+0.04)²⁰))} - (20/0.04(1 + 0.04)²⁰) ]

= 52000[ ((1.04)²⁰ - 1) / (0.04(1.04)²⁰) ] - (2000)[ {((1.04)²⁰ - 1) / ((0.04)²(1.04)²⁰))} - (20/0.04(1.04)²⁰) ]

= 52000[ ((2.191123 - 1) / (0.04(2.191123) ] - (2000)[ {((2.191123 - 1) / ((0.0016)(2.191123))} - (20/0.04(2.191123) ]

= 52000(1.191123/0.08764) - (2000){( 1.191123/0.003506) - (20/0.87645)}

= 52000(13.59033) - (2000)(339.7582 - 228.1935)

= 52000(13.59033) - (2000)(111.5647)

= 706695.6 - 223129.4

= 483,566.2 ≈ 483,566

Therefore its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

4 0
3 years ago
One hundred ninety-two students were surveyed about their favorite kind of TV programs. The results are shown in the table. Whic
trapecia [35]

Answer:

Music was 25%

Step-by-step explanation:

5 0
3 years ago
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