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3 years ago

7,7.5,8,8.5,9 common difference

Mathematics

2 answers:

raketka [301]3 years ago

3 0

Answer:

$0.5$

Step-by-step explanation:

$9-8.5$

$=0.5$

zhannawk [14.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

subtract 7 from 7.5 to get .5

to prove your answer subtract 8.5 from 9

subtract any from the left to the one to the immediate right to get .5

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Find the value of x in the isosceles triangle shown below.

miss Akunina [59]

Answer:

D. x=4

Step-by-step explanation:

We can solve this with the Pythagorean Theorem for the right triangle that we can see (which is half of the triangle).

The bottom length is 3 and the hypotenuse is 5.

The Pythagorean Theorem is a²+b²=c².

We can plug this in:

3²+x²=5²

9+x²=25

x²=16

x=4

8 0

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 3x+5y=4?

kap26 [50]

Answer:

5/3 or 1.67

Step-by-step explanation:

Find the slope of the original line

3x+5y=4 Subtract 3x from both sides

5y = - 3x + 4 Divide both sides by 5

y = (-3/5)x + 4

The original line has a slope of - 3/5 or - 0.6

Find the slope of the perpendicular line

m1 * m2 = - 1

m1 = - 3/5

m2 = -1/(-3/5)

m2 = 5/3

The slope of the perpendicular line is

5/3 or 1.67

8 0

3 years ago

How do you write 300,000,000+40,000,000+7,000,000+300,000+10,000+6,000+20+9 in standard form

kodGreya [7K]

it is 34,731,629 gust put the numbers to gater

5 0

3 years ago

Jason knows that the equation to calculate the period of a simple pendulum is , where T is the period, L is the length of the ro

Brrunno [24]

Answer-

$\boxed{\boxed{L=\dfrac{g}{4\pi^2 f^2}}}$

Solution-

The equation for time period of a simple pendulum is given by,

$T=2\pi \sqrt{\dfrac{L}{g}}$

Where,

T = Time period,

L = Length of the rod,

g = Acceleration due to gravity.

Frequency (f) of the pendulum is the reciprocal of its period, i.e

$f=\dfrac{1}{T}\ \Rightarrow T=\dfrac{1}{f}$

Putting the values,

$\Rightarrow \dfrac{1}{f}=2\pi \sqrt{\dfrac{L}{g}}$

$\Rightarrow (\dfrac{1}{f})^2=(2\pi \sqrt{\dfrac{L}{g}})^2$

$\Rightarrow \dfrac{1}{f^2}=4\pi^2 \dfrac{L}{g}$

$\Rightarrow L=\dfrac{g}{4\pi^2 f^2}$

8 0

3 years ago

Read 2 more answers

The vertex form of a function is g(x) = (x – 3)2 + 9. How does the graph of g(x) compare to the graph of the function f(x) = x2?

Alekssandra [29.7K]

we have

$g(x)=(x-3)^{2}+9$

This is the equation of a vertical parabola with vertex at point $(3,9)$

The parabola open upward------> the vertex is a minimum

$f(x)=x^{2}$

This is the equation of a vertical parabola with vertex at point $(0,0)$

The parabola open upward------> the vertex is a minimum

the rule of the translation is

$f(x)------> g(x)$

$(x,y)-----> (x+3,y+9)$

that means

the translation is $3$ units to the right and $9$ units up

the graph of the function g(x) is the translated graphic of the function f(x) $3$ units to the right and $9$ units up

therefore

the answer is

g(x) is shifted $3$ units right and $9$ units up

8 0

3 years ago

Read 2 more answers