Question

After finishing college, Daniel had interviews with SeaWorld and the Central Park Zoo. The probability of receiving an offer from SeaWorld is 35%. The probability of receiving an offer from the Central Park Zoo is 48%. The probability of Daniel getting an offer from both SeaWorld and the Central Park Zoo is 15%.
Determine the probability of receiving an offer from either SeaWord or Central Park Zoo but not both. ____________

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$68\%$

Step-by-step explanation:

Let A be the event that Daniel receives call from SeaWorld.

Probability of event A, P(A) = $35\%$

Let B be the event that Daniel receives call from Central Park Zoo.

Probability of event B, P(B) = $48\%$

Probability that Daniel receives calls from both SeaWorld and Central Park Zoo:

$P(A \cap B) = 15\%$

We know that formula:

Probability that Daniel receives call from either SeaWorld or Central Park Zoo but not both:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)\\\Rightarrow P(A \cup B) = 35\% + 48\% - 15\%\\\Rightarrow P(A \cup B) = 68\%$

Hence, required probability is $68\%$.