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zysi [14]
3 years ago
10

Tameka built 1/2 of a shed on Monday and 2/5 of the shed on Tuesday. Tameka finished building the shed of Wednesday. What fracti

on of the shed did she build of Wednesday?
EXPLAIN STEP BY STEP!
Mathematics
1 answer:
Doss [256]3 years ago
4 0

Step One

Find the sum of the fractions for Monday and Tuesday

1/2 + 2/5

The common denominator for these 2 days is 10

1/2: 1*5/(2*5) = 5/10

2/5:2*2/(2*5) = 4/10

Add these two equivalent fractions together.

5/10 + 4/10 = 9/10

The first 2 days resulted in 9/10 of the shed being completed.

Step Two

Find out how much (in terms of fractions) is left of the shed.

Let the whole shed = 1

Let what has been done = 9/10

What remains is 1 - 9/10 = 1/10

Answer: 1/10 of the shed needs to be done

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We are asked to factor out the expression:

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2 years ago
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Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 8}  \\ f(4) = 3 \end{cases}}

The nth root of a can contain negative number only if n is an odd number.

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 2 \times -  2 \times   - 2}  \\ f(4) = 3 \end{cases}} \\  \large{  \begin{cases} f( - 8 ) =  - 2\\ f(4) = 3 \end{cases}}

Answer

  • f(-8) = -2
  • f(4) = 3
6 0
2 years ago
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