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Rudik [331]
3 years ago
10

Given the domain values {-3, 0, 3} what is the range for the equation f(x) = −5x + 2? Question options: {-3, 0, 3} {-6, 2, 6} {-

15, 0, 15} {-13, 2, 17}
Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

The range is the set of all possible output, as you feed the function with all possible inputs. Since our inputs (domain) are -3, 0, 3, our outputs are

f(-3) = 15+2 = 17\\f(0)=0+2 = 2\\f(3) = -15+2 = -13

So, the range is

\{-13, 2, 17\}

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The information below applies to a competitive firm that sells its output for $40 per unit.
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3 years ago
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4/5(x+5/6)-2/3(x-1/4)=7/6
solniwko [45]

Answer and Step-by-step explanation:

Hello~let's~solve~your~equation:

<u>Step 1: Simplify both sides of the equation:</u>

(\frac{4}{5}) (x)+(\frac{4}{5})(\frac{5}{6})+\frac{-2}{3}x+\frac{1}{6}    =\frac{7}{6}  (Distribute)

\frac{4}{5}x+\frac{2}{3}+\frac{-2}{3}x+\frac{1}{y\6}=\frac{7}{6}

(\frac{5}{5}x+ \frac{-2}{3}x )+(\frac{2}{3}+ \frac{1}{6})=\frac{7}{6} (Combine~like~terms)

\frac{2}{15}x+\frac{5}{6}=\frac{7}{6}

<u>Step 2: Subtract 5/6 from both sides:</u>

\frac{2}{15}x+\frac{5}{6}- \frac{5}{6} =\frac{7}{6} -\frac{5}{6}

\frac{2}{15}x=\frac{1}{3}

<u>Step 3: Multiply both sides by 15/2:</u>

(\frac{15}{2}) *(\frac{2}{15}x)=(\frac{15}{2})*(\frac{1}{3})

x= \frac{5}{2}

4 0
3 years ago
What is the greatest common factor 6c^5 15c^6
Sholpan [36]
3c^5

The greatest number that goes into both 6 and 15 is 3, and both values of c have at least c^5.

hope this helps :)
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3 years ago
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