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alekssr [168]
2 years ago
10

Use the image from problem 11 to answer this problem.

Mathematics
1 answer:
guajiro [1.7K]2 years ago
4 0

Answer:

34.

Step-by-step explanation:

All angles of a triangle combined equal 180, so if 1 angle measures 146, subtract 146 from 180. 180-146=34

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Vertical lines m and n are intersected by lines k and j. At the intersection of lines m and k, the bottom right angle is (x minu
Nezavi [6.7K]

Using the same-side interior angles theorem, the values of x and y are:

x = 80

y = 130

<h3>What is the Same-side Interior Angles Theorem?</h3>

The same-side interior angles theorem states that two interior angles on same side of a transversal are supplementary.

(x - 30) and (x + 50) are same-side interior angles, therefore:

(x - 30) + (x + 50) = 180

Solve for x

x - 30 + x + 50 = 180

2x + 20 = 180

2x = 180 - 20

2x = 160

x = 160/2

x = 80

(x - 30) + y = 180

Plug in the value of x

(80 - 30) + y = 180

50 + y = 180

y = 180 - 50

y = 130

Learn more about the same-side interior angles theorem on:

brainly.com/question/13867198

#SPJ1

5 0
2 years ago
Construct a quadrilateral Zeus in which NE=7 cm ,EW = 6 cm &lt;N=60° , &lt;E=110° and &lt;S=85°​
aev [14]

Answer:

look it up online

Step-by-step explanation:

look it up online

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME [99 POINTS[
Ierofanga [76]
I think it b havent seen a relation(a)
3 0
4 years ago
Read 2 more answers
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
3 years ago
HELP!!!!!!!!!!<br><br> Hi there! I really need help with this question.
hammer [34]
I believe it's A. Day 1 decreased by half from 8 would be 4. Day 2 decreased by half from 4 would be 2. Day 3 decreased by half from 2 would be 1. then .5 would be decrease by. 25, which would be .75. I hope that makes sense:)
4 0
3 years ago
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