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blagie [28]
3 years ago
12

Divide. 5/7 ÷ 3 Express the answer in simplest terms.

Mathematics
1 answer:
vlada-n [284]3 years ago
7 0

Divide:


\frac{5}{7} : 3 = \frac{5}{7} x \frac{1}{3} = \frac{5x1}{7x3} = \frac{5}{21}



To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.


Result:

5/7 ÷ 3 = \frac{5}{21}

≅ 0.2380952


Hope this helped


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The right rectangular prism is made up of 48 cubes. Each cube has an edge length of inch. What is the volume of this prism?
Gnesinka [82]

Given:

  • The right rectangular prism is made up of 48 cubes.
  • Each cube has an edge length of 1/4 inch.

~

To Find:

  • What is the volume of this prism?

~

Solution:

~

<u>Using formula: </u>

~

  • \sf \pmb {Volume  \: of \:  cube =  {(side)}^{3} }

~

Substituting values in the formula:

~

\sf \longrightarrow  \dfrac{1}{4}  \times  \dfrac{1}{4}  \times  \dfrac{1}{4}

\sf \longrightarrow \dfrac{1}{64}  \:  {inch}^{3}

~

Now,

Volume of 48 such cubes = Volume of 1 cube × 48 cubes

~

\sf \longrightarrow \dfrac{1}{64}  \times 48

\sf \longrightarrow \dfrac{48}{64}

\sf \longrightarrow \dfrac{3}{4}  \:  {inch}^{3}

~

Hence,

  • Volume of prism is <u>3/4 inch^3</u>
7 0
3 years ago
Find the area of a triangle and semi circle where the diameter is 18 and the height is 14 using 3.14
Readme [11.4K]

Answer:

triangle A= 1/2bh

1/2(18)(14)= 126

semi circle 3.14(9)^2 divided by 2 = 127.17

Triangle Area plus semi circle Area = 126+127.17= 253.17

4 0
2 years ago
2y+3x² +5+y+2x+x²+2 what are the coefficients?
saw5 [17]

Answer: 200

The quadratic function f(x) = a(x - h)2 + k, a not equal to zero, is said to be in standard form. If a is positive, the graph opens upward, and if a is negative, then it opens downward. The line of symmetry is the vertical line x = h, and the vertex is the point (h,k).

Any quadratic function can be rewritten in standard form by completing the square. (See the section on solving equations algebraically to review completing the square.) The steps that we use in this section for completing the square will look a little different, because our chief goal here is not solving an equation.

Note that when a quadratic function is in standard form it is also easy to find its zeros by the square root principle.

Example 3.

Write the function f(x) = x2 - 6x + 7 in standard form. Sketch the graph of f and find its zeros and vertex.

f(x) = x2 - 6x + 7.

= (x2 - 6x )+ 7.        Group the x2 and x terms and then complete the square on these terms.

= (x2 - 6x + 9 - 9) + 7.

We need to add 9 because it is the square of one half the coefficient of x, (-6/2)2 = 9. When we were solving an equation we simply added 9 to both sides of the equation. In this setting we add and subtract 9 so that we do not change the function.

= (x2 - 6x + 9) - 9 + 7. We see that x2 - 6x + 9 is a perfect square, namely (x - 3)2.

f(x) = (x - 3)2 - 2. This is standard form.

From this result, one easily finds the vertex of the graph of f is (3, -2).

To find the zeros of f, we set f equal to 0 and solve for x.

(x - 3)2 - 2 = 0.

(x - 3)2 = 2.

(x - 3) = ± sqrt(2).

x = 3 ± sqrt(2).

To sketch the graph of f we shift the graph of y = x2 three units to the right and two units down.

If the coefficient of x2 is not 1, then we must factor this coefficient from the x2 and x terms before proceeding.

Example 4.

Write f(x) = -2x2 + 2x + 3 in standard form and find the vertex of the graph of f.

f(x) = -2x2 + 2x + 3.

= (-2x2 + 2x) + 3.

= -2(x2 - x) + 3.

= -2(x2 - x + 1/4 - 1/4) + 3.

We add and subtract 1/4, because (-1/2)2 = 1/4, and -1 is the coefficient of x.

= -2(x2 - x + 1/4) -2(-1/4) + 3.

Note that everything in the parentheses is multiplied by -2, so when we remove -1/4 from the parentheses, we must multiply it by -2.

= -2(x - 1/2)2 + 1/2 + 3.

= -2(x - 1/2)2 + 7/2.

The vertex is the point (1/2, 7/2). Since the graph opens downward (-2 < 0), the vertex is the highest point on the graph.

Exercise 2:

Write f(x) = 3x2 + 12x + 8 in standard form. Sketch the graph of f ,find its vertex, and find the zeros of f. Answer

Alternate method of finding the vertex

In some cases completing the square is not the easiest way to find the vertex of a parabola. If the graph of a quadratic function has two x-intercepts, then the line of symmetry is the vertical line through the midpoint of the x-intercepts.

The x-intercepts of the graph above are at -5 and 3. The line of symmetry goes through -1, which is the average of -5 and 3. (-5 + 3)/2 = -2/2 = -1. Once we know that the line of symmetry is x = -1, then we know the first coordinate of the vertex is -1. The second coordinate of the vertex can be found by evaluating the function at x = -1.

Example 5.

Find the vertex of the graph of f(x) = (x + 9)(x - 5).

Since the formula for f is factored, it is easy to find the zeros: -9 and 5.

The average of the zeros is (-9 + 5)/2 = -4/2 = -2. So, the line of symmetry is x = -2 and the first coordinate of the vertex is -2.

The second coordinate of the vertex is f(-2) = (-2 + 9)(-2 - 5) = 7*(-7) = -49.

Therefore, the vertex of the graph of f is (-2, -49).

8 0
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Find the perimeter of a rectangle with a length of 12 feet and a width of 6 feet.
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Answer:

First one

Step-by-step explanation:

3s=5s-6

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