<span> y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9</span>(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
answer
A
Answer:
Step-by-step explanation:
<u>Subtract the values:</u>
- 19 1/12 - 8 5/12 =
- 18 13/12 - 8 5/12 =
- 18 - 8 + 13/12 - 5/12 =
- 10 + 8/12 =
- 10 8/12 =
- 10 2/3 in
Answer:
3 is what I think the answer is
In order to find the angle θ, in <u>radians</u>, whose<u> tangent</u> is 
you have to follow those steps
Step 1
Using a<u> calculator</u>
Find the angle θ
Remember that
the angle θ belong to the second quadrant
so
Angle θ=
Step 2
Convert degrees to <u>radians</u>
we know that
therefore
the answer is
the angle θ is 
It would be a scalene triangle as all angles are different
