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slavikrds [6]
2 years ago
7

PLEASE HURRY Fill in the blank:

Mathematics
2 answers:
makkiz [27]2 years ago
7 0

Answer:

This is slope-intercept form: y = (-3/4)x + 3

The slope is: -3/4

The y-intercept is: 3

Step-by-step explanation:

3x + 4y - 12 = 0

Isolate y

3x - 3x + 4y -12 + 12 = -3x + 12

Simplify

4y = -3x + 12

Divide 4 on each side to get y by itself

4y/4 = -3x/4 + 12/4

Simplify

y = (-3/4)x + 3

This is slope-intercept form: y = (-3/4)x + 3

The slope is: -3/4

The y-intercept is: 3

GREYUIT [131]2 years ago
3 0

Answer: I calculated it and my answer I got was that the slope-intercept form: was y = (-3/4)x + 3

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Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

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  • L(8, -4)
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We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

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As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

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