56x² - 49x + 14 = 7(8x² - 7x +2)
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The greatest common factor of 56, 49, and 14 is 7.
12+8k=48
=>8k=36
=>k=36/8
=>k=4.5
Show me the picture of the octagon. But remember that if the diameter is shown than always do half of the diameter to get the radius. Hope this helps
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
3.72769
Step-by-step explanation:
Use tangent - tan74 = 13/x
Solving for x gives you 3.72769
I'm not sure how many decimal places you need, so there are most of them
Hopefully this helps- let me know if you have any questions
