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Afina-wow [57]
2 years ago
13

On a coordinate plane, a curved line with a maximum value of (negative 1, 2) crosses the x-axis at (negative 3, 0) and (1, 0), a

nd crosses the y-axis at (0, 1.5).
What are the x-intercepts of the graphed function?

(–3, 0) and (0, 1.5)
(–3, 0) and (1,0)
(–1, 2) and (1, 0)
(0, 1.5) and (1, 0)
Mathematics
2 answers:
vekshin12 years ago
6 0

Answer:

The answer would be B= (–3, 0) and (1,0)

Aleksandr-060686 [28]2 years ago
5 0

9514 1404 393

Answer:

  (–3, 0) and (1,0)

Step-by-step explanation:

The x-intercepts are where the curve crosses the x-axis. Your problem statement tells you ...

  "crosses the x-axis at (negative 3, 0) and (1, 0)"

This means the x-intercepts are (-3, 0) and (1, 0).

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Answer:

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Step-by-step explanation:

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2 years ago
Multiply 3i(−1 + 2i). What is the simplified version written in standard form, a + bi, where a and b are real numbers?
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3i (-1) + (2i)(3i) Look at the first set of brackets around the -1
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4 0
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Explain how you know the values of the digits in number 58
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3 0
2 years ago
A group of researchers wants to know whether men are more likely than women to contract a novel coronavirus. They surveyed two r
olasank [31]

Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

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Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

                    p_{1} = \frac{360}{390} = 0.9230

second sample proportion

                  p_{2} = \frac{47}{52} = 0.9038

Step(ii):-

Null hypothesis : H₀ : There is no difference  proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

 

Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} }  } }

where

          P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1}+n_{2}  }

         P =  0.920

Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52}  } )}

Test statistic Z =  0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

Null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women







7 0
3 years ago
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