Express this number in standard form.<br> 1.588 \times 10^{-1} = {?}1.588×10 <br> −1<br> =?

In variables estimation sampling, the sample standard deviation is used to calculate the?

Nikitich [7]

The sample standard deviation is used to calculate the determine the spread of estimates for a set of observations (i.e., a data set) from the mean (average or expected value).

<h3>What is sample standard deviation?</h3>

The spread of a data distribution is measured by standard deviation. The average distance between each data point and the mean is measured.

The sample standard deviation (s) is a measurement of the variation from the expected values and is equal to the sample variance's square root.

where

s = sample standard deviation

N = the number of observations

$xi$ = the observed values of a sample item

$\overline {x}$ = the mean value of the observations

Learn more about simple standard deviation, refer:

brainly.com/question/26941429

#SPJ4

3 0

2 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Can anyone help me with this math question

Lynna [10]

Answer:

89 seats are not being used

Step-by-step explanation:

You subtract the seats being used by teachers

342 - 75 =267

Change 2/3 into a percentage = 66.6%

Find 66.6% of 267= 177.8 (I rounded up to 178)

Then subtract 177.8/178 from 267 to find the amount of seats not being used.

The amount of seats not being used would come down to 89 seats.

I hope this helps!

4 0

3 years ago

8. What happens to acceleration when the velocity changes by the same<br> amount over time?

Nookie1986 [14]

Answer:

The acceleration will also be uniform when velocity changes by the same amount over time.

Step-by-step explanation:

Acceleration is defined as a rate of change of velocity per unit time.

Unit of the acceleration is m/ $s^{2}$

So,here when the velocity changes by the same amount over time, the change here will be <u>UNIFORM</u>.

Hence, the acceleration will also be uniform when velocity changes by the same amount over time.

3 0

3 years ago

Please help me with this question

kotegsom [21]

Answer:

24 and 20

Step-by-step explanation:

opposite sides are equal

6 0

2 years ago

Express this number in standard form. 1.588 \times 10^{-1} = {?}1.588×10 −1 =?