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3 years ago

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Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

5 0

Answer:

72 degrees

Step-by-step explanation:

let the ratio be 2x and 3x

2x + 3x =180° ( co interior angles )

5x = 180°

x = 180 ÷ 5

x = 36°

And the smaller angle = 2 × 36° = 72°

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Aunt Kendra is pricing cakes for a baby shower she is throwing. She wants one large cake shaped like a duckling and also some cu

Andreas93 [3]

Answer:

$70

Step-by-step explanation:

Middletown Equation:

1c +50 = T

Sweet Shoppe Equation:

2c + 30 = T

Set equations equal to one another and solve for first for cupcakes then for cost.

1c + 50 = 2c + 30

c+ 20 = 2c

20 = c (twenty cupcakes would be ordered)

Now insert into either equation ( or both to check)

1(20) + 50 = 70

2(20)+ 30 = 70

Total cost would be $70

HOPE THIS HELPS!!!

4 0

2 years ago

You are given a line that has a slope of 4 and passed through the point (3/8, 1/2). Which statements about the question of the l

alexgriva [62]

Answer:

Statement 1, 2 and 4 are true where as statement 3 is not true.

Step-by-step explanation:

Statement 1: The y-intercept is -1

Point (3/8, 1/2)

Slope = m = 4

y = mx + c

1/2 = 4(3/8) + c

1/2 = 3/2 + c

1/2 = 3/2 + 2c/2

-2 = 2c

c = -1

This statement is true as the y-intercept is -1.

Statement 2: The slope intercept equation is y= 4x - 1

slope = m = 4

y-intercept = c = -1

y = mx + c

y = 4x - 1

This statement is true as the slope intercept equation is y= 4x -1

Statement 3: The point slope equation is y - 3/8 = 4 (x - 1/2)

Point slope equation: y - y1 = m (x - x1)

Points: (x, y) (3/8, 1/2)

y1 = 1/2

x1 = 3/8

Slope = m = 4

y - 1/2 = 4 (x - 3/8)

This statement is not true as the slope intercept equation is y - 1/2 = 4 (x - 3/8) instead of y - 3/8 = 4 (x - 1/2).

Statement 4: The point (3/8, 1/2) corresponds to (x1, y1) in the point slope form of the equation

This statement is true as shown in statement 3's explanation where x1 = 3/8 and y1 = 1/2

6 0

3 years ago

#4 home do I find which one it is?

lina2011 [118]

$\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}$

$\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}$

for example, let's look at the first set

y+3x =5 or y = -3x+ 5
and y = -3x + 2
y = m + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution

8 0

4 years ago

Can you help me solve this?

Wittaler [7]

Answer:

y=-1/2x+4 Is your answer

Step-by-step explanation:

y=mx+b

3=2x+4

-1=2x

x=-1/2

You already know y is 4 so y=-1/2x+4

4 0

3 years ago

Write the expression without radicals, using only positive exponents

Mamont248 [21]

Answer:

$\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}$

Step-by-step explanation:

∵∛x = (x)^1/3

∴ $\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}$

So you can replace the radicals by fractional exponents

7 0

3 years ago

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