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Svetllana [295]
3 years ago
9

Lupe bought 8 pounds of pretzels at a local wholesaler for $18. Her friend Charles bought 6 pounds of pretzels at the supermarke

t for $15. Charles thinks he got the better deal because $15 is less than $18
How much would Charles have spent at the supermarket if he had purchased the same amount of pretzels as Lupe bought at the wholesaler? Show your work explain your answer, in a paragraph
Mathematics
2 answers:
Novay_Z [31]3 years ago
3 0

Answer:

20

Step-by-step explanation:

Charle would have spent that much because one pound is 2.50

15 divided by 6=2.50

2.50x8=20

alexdok [17]3 years ago
3 0

Answer:

Charles would've spent $20 at the supermarket if he bought the same amount of pounds as Lupe.

Step-by-step explanation:

18÷8= 2.25

2.25 is the amount of money per pound at the wholesaler.

15÷6= 2.50

2.50 is the amount of money per pound at the supermarket.

2.50x8=  20

Charles would've spent $20 if he bought the same amount of pounds as Lupe. Since one pound cost 2.50 at the supermarket, 8 times 2.50 is 20. He would actually spend more at the supermarket than the wholesaler.

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The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a ye
zloy xaker [14]

Answer:

Number of​ restaurant-purchased meals eaten in a​ restaurant = 70

Number of​ restaurant-purchased meals eaten in a​ car = 22

Number of​ restaurant-purchased meals eaten in a​ home = 60

Step-by-step explanation:

Let the number of people that will eat in a restaurant be R.

Let the number of people that will eat in a car be C.

Let the number of people that will eat in a home be H.

From the information given in the problem we have,

R+C+H = 152 ____equation (1)

C+H-R = 12 ____equation (2)

R = H+10 ____equation (3)

1) Plugging in R=H+10 from equation 3 into the equation 2, we get

C+H-R=12

=> C+H-(H+10)=12

=> C+H-H-10=12

2) Cancelling out +H and -H, we get

C-10=12

3) Add 10 to both sides

C-10+10=12+10

4) Cancelling out -10 and +10, we get

C=22

5) Plugin C=22 in equation 1, we have

R+C+H = 152

=> R+22+H=152

Subtract 22 from both sides,

R+22+H-22=152-22

Cancelling out +22 and -22 from the left side, we get

R+H=130 ____let it be equation (4)

6) Plugin C=22 in equation 2, we have

C+H-R = 12

22+H-R = 12

Subtracting 22 from both the sides, we get

22+H-R-22 = 12-22

Cancelling out +22 and -22 from the left side,

H-R = -10 ____let it be equation (5)

7) Adding equation 4 and equation 5, we get

(R+H)+(H-R) = 130 + (-10)

=> R+H+H-R = 130-10

8) Cancelling out R and -R from the left side, we get

2H = 120

9) Dividing both sides by 2, we get

\frac{2H}{2} = \frac{120}{2}

10) Cancelling out the 2's from the left side, we have

H=60

11) Plugging in C=22 and H=60 in the equation 1, we have

R+C+H = 152

=> R+22+60=152

=> R + 82 = 152

12) Subtracting 82 from both the sides, we get

R + 82 -82 = 152 -82

13) Cancelling out +82 and -82 from the left side, we get

R = 70

<em>So, C=22, H=60, R=70</em>

8 0
2 years ago
Sharon earns 4% Commission on the items that she sells one week she earns $150 in commission what is the total value of the item
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