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Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer: About 4
Step-by-step explanation:
16 divided by 3 2/3 is 4. decimal so round that and about 4 is you’re answer.
Hello there!
2(x - 3) = 2x + 5
Let's start by using the distributive property for the left side.
(2)(x) + (2)(-3) = 2x + 5
2x - 6 = 2x + 5
Then we need to add 6 to both sides
2x - 6 + 6 = 2x + 5 + 6
2x = 2x + 11
We need to transfer 2x on the left side, we gonna do that by subtracting 2x from both sides
2x - 2x = 2x + 11 - 2x
0 = 11
Thus,
There are no solutions.
I hope this helps!
Good luck with your career!
Answer:
I can help but for a price.
Step-by-step explanation:
