Yes because a triangles are is 1/3 b x h and a rectangles area is just b x h. The triangle would get smaller because it doesn’t have one corner, and the rectangle would keep a constant size.
Answer:
h(x) = 1/4x
Step-by-step explanation:
To find the inverse, first we rewrite the function using y instead of f(x):
y = 4x
Next we switch x and y:
x = 4y
Solve for y by dividing both sides by 4:
x/4 = 4y/4
x/4 = y
1/4x = y
This is a stupid question. The teacher who asked this needs to go back to school.
A = x⁴ - 9y²
That's going to be a number. As long as it's positive we can choose any length for our rectangle L and we can compute the width by W=A/L. So the correct answer is the dimensions are L by (x⁴ - 9y²)/L.
They don't want the correct answer. They want you to factor this expression. We'll do it, but don't believe for a second this factoring somehow constrains the possible dimensions of some rectangle.
We use the difference of two squares, a²-b² = (a+b)(a-b)
A = x⁴ - 9y² = (x²)² - (3y)² = (x²+3y)(x²-3y)
Answer: x²+3y by x²-3y
Explain how you can use a straightedge and a compass to construct and angle that is both congruent and adjacent to a given angle?
Answer: for this you will simply have to use the straightedge to draw two parallel lines and then you draw a line that goes through them that is perpendicular. You then use the compass to measure the angles, they should be congruent and adjacent.
I hope it helps, Regards.
