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vichka [17]
3 years ago
8

Using Ratios to Solve Problems - Item 1457 Question 4 of 7 Evan's family drove to a theme park for vacation. They drove the same

speed throughout the trip. The first day, they drove 300 300 miles in 6 6 hours. The second day, they drove 250 250 miles in 5 5 hours. The third day, they arrived at the park after driving for 3 3 hours. How many miles did they drive on the third day?
Mathematics
1 answer:
azamat3 years ago
5 0

Answer:

150 miles

distance travelled on the third day = 150 miles

Step-by-step explanation:

Note: it was given that they drove the same speed throughout the trip. That means their speed is constant for all days;

For the first day

distance = 300 miles

time = 6 hours

Speed = distance/time

Speed = 300/6 = 50 mph

on the third day;

time = 3 hours

Speed = speed on first day = 50 mph

distance = speed × time

distance = 50 mph × 3 hours

distance = 150 miles

distance travelled on the third day = 150 miles

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300,000,000+4,000,000+800,000+400

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MATH HELP!!!!!<br><br> If y = 15 when x = 2, what is the value of x when y = 7?
Ede4ka [16]

<u>Direct Variation:</u>  \frac{y}{x} = k

\frac{15}{2} = k

when y = 7:      \frac{7}{x} = \frac{15}{2}

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\frac{14}{15} = x

<u>Inverse variation:</u>   y*x = k

15 * 2 = k

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3 0
3 years ago
Find the measure of c. A. 40 B. 70 C. 90 D. 50
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Answer:

D. 50

Step-by-step explanation:

a = 90° (angle subtended in semicircle)

a + c + 40° = 180° (by angle sum postulate of a triangle)

90° + c + 40° = 180°

c + 130° = 180°

c = 180° - 130°

c = 50°

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What is the area of a circle whose diameter is 32 inches? Use π=3.14 in your calculations. Show your work.
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5 0
3 years ago
A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr
ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so \pi = 0.30

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so n = 10

We want to find P(X = 1). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is P(X > 1)

We have that:

P(X \leq 1) + P(X > 1) = 1

P(X > 1) = 1 - P(X \leq 1)

We also have that:

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282

So

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493

Finally

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507

There is a 85.07% probability that more than 1 has the marker.

3 0
3 years ago
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