If f(x) = (ln x)^2, then f''( sqrt of e) is equal to _____.

2 answers:

N76 [4]3 years ago

7 0

Hello,

f(x)=(Ln(x))²

f'(x)=2Ln(x)*1/x=2Ln(x)/x

f''(x)=2(1/x*x-Ln(x)*(-1/x²))/x²=2/x²+2*Ln(x)/x^4

f'(√e)=2/e+2/e²=2(e+1)/e²=1,006429....

jeyben [28]3 years ago

5 0

Base on your question where as the function of f(x) is equals to (ln x) to the power of 2, then f"(sqrt of e) , based on my calculation, and the way i understand the function i came up with a formulation that could fit to find the answer to your question and the answer is 1,006, 429

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Work out the percentage change to 2 decimal places when a price of £99 is increased to £111.

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Answer:

0.12

Step-by-step explanation:

The percentage change formula depends if the price goes up or down. Since this goes up, we have the positive percentage change formula. This is $\frac{ a_n - a_1}{a_1}$ where $a_n$ is the new price and $a_1$ is the original price. Plugging in our values, we get $\frac{111-99}{99} = \frac{12}{99} = 0.\overline{12}$ . Since this is to two decimal places we get 0.12 as our answer.