Question

If f(x) = (ln x)^2, then f''( sqrt of e) is equal to _____.

Answer 1

Hello,

f(x)=(Ln(x))²

f'(x)=2Ln(x)*1/x=2Ln(x)/x

f''(x)=2(1/x*x-Ln(x)*(-1/x²))/x²=2/x²+2*Ln(x)/x^4

f'(√e)=2/e+2/e²=2(e+1)/e²=1,006429....

Answer 2

Base on your question where as the function of f(x) is equals to (ln x) to the power of 2, then f"(sqrt of e) , based on my calculation, and the way i understand the function i came up with a formulation that could fit to find the answer to your question and the answer is 1,006, 429