Add 4 to boh sides
t/5+4-4=9+4
t/5+0=13
t/5=13
times 5/1 both sides
5t/5=5*13
1t=65
t=65
Answer:
The first one is 648 and the second one is 11,600
Step-by-step explanation:
We have
So
The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with
and this happens if <em>a</em> = 1 and <em>b</em> = -1.
To confirm, we have
as required.
Hello from MrBillDoesMath!
Answer:
x = log5 / ( (1/2)log6 + log5)
approximately 0.642
Discussion:
Take the logarithm of both sides ( to "pull" the exponents down so we can work on them!)
6^(x/2)) = 5^(1-x)
log ( 6^(x/2)) = log (5^(1-x)) => using log (a^n) = n log a
(x/2) log6 = (1-x) log5 => add x log5 to both sides
(x/2) log6 + xlog5 = log5 - xlog5 + xlog5 =>
(x/2) log6 + xlog5 = log5 => factor x from the lhs
x ( (1/2) log6 + log5) = log5 =>
x = log5 / ( (1/2)log6 + log5)
The above can be further simplified but that's as far as I want to take it.The value of x is approx equal to 0.642
Thank you,
MrB
ok so 7 divided by 12 is 0.5833333 repeating so -0.72 is less because the bigger one is always less in the negatives
