What does x= in the equation?
1 answer:
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<em>Answer:</em>
<em>[-3,3]</em>
<em>Step-by-step explanation:</em>
<em>Write the problem as a mathematical expression.</em>
<em>4x^2+y^2=36</em>
<em>Subtract 4x^2 from both sides of the equation.</em>
<em>y^2=36-4x^2</em>
<em>Take the square root of both sides of the equation to eliminate the exponent on the left side.</em>
<em>y= + and - </em><em />
<em>The complete solution is the result of both the positive and negative portions of the solution.</em>
<em>y= </em><em />
<em /><em />
<em>Set the radicand in </em><em> greater than or equal to 0 to find where the expression is defined.</em>
<em /><em />
<em>So your answer would be [-3,3]</em>
Answer:
Step-by-step explanation:
x² + 2x - 3 + y² = 5
Strategy:
Convert the equation to the centre-radius form:
(x - h)² + (y - k)² = r²
The centre of the circle is at (h, k) and the radius is r .
Solution:
Move the number to the right-hand side.
x² + 2x + y² = 8
Complete the square for x
(Take half the coefficient of x, square it, and add to each side of the equation)
(x² + 2x + 1) + y² = 9
Complete the square for y
The coefficient of y is zero.
(x² + 2x + 1) + y² = 9
Express the result as the sum of squares
(x + 1)² + y² = 3²
h = -1; k = 0; r = 3
The centre of the circle is at
The graph of the circle below has its centre at (-1,0) and radius 3.
