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Bas_tet [7]
2 years ago
8

3 Which expression is equivalent to 19 - 27?

Mathematics
2 answers:
Elanso [62]2 years ago
4 0

Answer: 19 + (-27)

Step-by-step explanation:

aleksandr82 [10.1K]2 years ago
3 0

Answer:

19 +-27

Step-by-step explanation:

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At a country concert, the ratio of number of boys to the number of girls is 2:7. If there are 250 more girls than boys, how many
Juliette [100K]

Answer:

100 boys at the concert

Step-by-step explanation:

When changing the ratio between the number of boys to the number of girls, it always has to be equivalent to the original ratio 2:7

So, convert the ratio 2:7 to a different ratio, but it still has to be equivalent to the ratio 2:7. By doing that, multiply both sides of the 2:7 ratio by 50:

  2   :   7

×50   ×50

To get:

100:350  ⇒  This ratio means that the ratio between the number of boys to the number of girls is now 100:350, but that’s okay to have because it’s still equivalent to the original 2:7 ratio.

So, using the new ratio 100:350, this means that there are 100 boys at the concert and 350 girls at the concert, and 350 is 250 more than 100 which proves what the question is asking. So there are 100 boys at the concert.

<u>Answer:</u> 100 boys at the concert

<em>I hope you understand and that this helps with your question! </em>:)

7 0
2 years ago
Use an algebraic rule to describe a translation right 4 units and down 2 units.
romanna [79]
(x+4,x-2) I think..,,
7 0
3 years ago
Read 2 more answers
What is one fourth of a number decreased by 10,is -50 <br>​
Rashid [163]

1/4x - 10 = -50

1/4x = one forth of a number

-10 is decreased by 10

= -50 means is -50

5 0
3 years ago
Read 2 more answers
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
consider quadrilateral ABCD as graphed above. rotate ABCD 90° clockwise about the origin, then dilate with a scale factor of 3/2
saw5 [17]

Answer:

A”=three possible answers (10.5) (21/2) or (10 1/2)

B”=9

C”=3

D”=(4.5) (9/2) or (4 1/2)

Step-by-step explanation: just cause

5 0
3 years ago
Read 2 more answers
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