Answer:
16x11/y (i hope)
Step-by-step explanation:
Answer:
f(y) = 4y2 - 4v
f(y) = 4y² - 4(-4) = 4y² + 16
f(y) = 4y² - 4(-3) = 4y² + 12
f(y) = 4y² - 4(-2) =4y² + 8
f(y) = 4y² - 4(-1) = 4y² + 4
Step-by-step explanation:
I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.
212= 2 X 2 X 53
212= 4X 53
