I'm not 100% sure if I'm doing it the right way, but I think the answer is the factorial of the number of letters divided by the factorials of the number of elements of each kind of element (in this case, the same letters)
9!/1!4!1!2!1!
= 9 · 8 · 7 · 6 · 5 · 4!/4!2!
= 9 · 8 · 7 · 6 · 5/2
= 9 · 4 · 7 · 6 · 5
= 63 · 120
= 7,560 permutations
Step-by-step explanation:
this creates 2 similar triangles.
that means all angles are the same. and all the side lengths of one triangle correlate to the corresponding side lengths of the other triangle by the same multiplication factor.
her shadow is 23.05 - 18.9 = 4.15 m long.
the factor between the shadow lengths is then
4.15 × f = 23.05
f = 23.05 / 4.15 = 5.554216867...
the same factor now applies to the relation of the heights :
1.45 × 5.554216867... = 8.053614458... m
rounded the tree is 8.05 m tall.
The answer is 20 because any number multiplied by 10 is going to be the same number but with a zero to the right of it for example 20 times 10 is 200 because u just add the zero to the right of the number have a great day
Answer:
60,000
Step-by-step explanation:
Evalute
6 x 10*4
6 x 10,000
60,000 is the standard form :)
AB = 6 cm, AC = 12 cm, CD = ?
In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.
Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°
In order to find ∠BCA, use the law of sines:
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA
Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°
Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°
In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.
12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
