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jek_recluse [69]
4 years ago
11

Two adjacent angles have non-common sides that form a straight line. if one angle is acute, what kind of angle is the other one,

how do you know?
Mathematics
1 answer:
kramer4 years ago
7 0

Answer:

Linear Pair, Because Adjacent Angles, Supplementary Angles, etc. Don't have any common factors in help to know which is the other one.

Step-by-step explanation:

- "Two adjacent angles have non-common sides that form a straight line. if one angle is acute, what kind of angle is the other one, how do you know?"

what kind of angle is the other one - Not really a(n) angle due to it being Linear Pair.

Linear Pair is Two Adjacent Angles that form a straight line.

No angle is able to do that except Linear Pair.

how do you know - By telling and seeing the main key points between angles and pairs. Pairs, as Linear Pair is "Angles" that form a straight line, in conclusion it basically means Linear Pair is angles into a line.

I hope this helps.

Peace.

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olga nikolaevna [1]

Answer:

Is this what you looking for

Step-by-step explanation:

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Hope this helps

7 0
3 years ago
Christopher bought a new watch at the store when they were having a 20\%20% off sale. If the regular price of the watch was \$48
Aleonysh [2.5K]

Answer:

38.4

Step-by-step explanation:

48*20%=9.6 48-9.6=38.4

7 0
4 years ago
PROBLEM: Four women (Linda, Lisa, Glenda, and Dee) are married to four men (Tom, Duane, Ron, and Ernie). From the clues, determi
UNO [17]

Answer:

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Step-by-step explanation:

I'll be waiting for an email.

4 0
3 years ago
type the slope intercept equation of the line that passes through the point (1,1)&(7,4) enter fraction in simplest form
9966 [12]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 1}}\quad ,&{{ 1}})\quad 
%   (c,d)
&({{ 7}}\quad ,&{{ 4}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{4-1}{7-1}\implies \cfrac{3}{6}\implies \cfrac{1}{2}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=\cfrac{1}{2}(x-1)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=\cfrac{1}{2}x-\cfrac{1}{2}\implies y=\cfrac{1}{2}x-\cfrac{1}{2}+1\implies y=\cfrac{1}{2}x+\cfrac{1}{2}
5 0
3 years ago
What’s the right answer?
galina1969 [7]

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .

I am unable to read all of the options in the picture you provided but I hope this helps! (:

6 0
3 years ago
Read 2 more answers
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