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dusya [7]
3 years ago
8

What are all the possible rectangles with whole-number side

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

So (L,W) possibilities are:

(1,4),(4,1),(2,3),(3,2)

That makes 4 possibilities.

Step-by-step explanation:

The perimeter of a rectangle is P=2L+2W where L is the length and W is the width.

We have that P=10, so 10=2L+2W.

10=2L+2W

10=2(L+W)  By factoring using the distributive property.

2(5)=2(L+W)  I factored 10 as 2(5).

If 2(5)=2(L+W), then 5=L+W.

Whole numbers are {0,1,2,3,4,5,6,7,8,9,10,...}. They are your counting numbers and 0.

I think they want natural numbers {1,2,3,4,...}.  This is also just called the counting numbers. The reason I think they want this because if one of the dimensions is 0, we won't actually have a rectangle.

So now looking for numbers from this set that satisfy: L+W=5.

L+W=5

1+4=5

4+1=5

2+3=5

3+2=5

So (L,W) possibilities are:

(1,4),(4,1),(2,3),(3,2)

That makes 4 possibilities.

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Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4
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equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of  (-9,-8) and (7,-4)

midpoint formula is

\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}

\frac{-9+7}{2} ,\frac{-8+-4}{2}

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}

slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4  and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10


3 0
3 years ago
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