Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:



So, if the population is in balance:



Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:



I hope you have a SUPER day!
Answer:
Explanation:
If any recessive phenotypic individuals result from the cross, then the unknown individual must carry the recessive allele, and have the heterozygous genotype. A testcross helps reveal the genotype of an organism when that organism shows the dominant trait, such as agouti coat color in rats.
B.
Both processes have a growth period called interphase, in which a cell replicates its genetic material and organelles in preparation for division. The two cells that result after meiosis I enter meiosis II very quickly, during the brief interphase period, no further DNA replication takes place.
C.
A. True
Answer: to study genetics
Supreme Court Landmarks
Participate in interactive landmark Supreme Court cases that have shaped history and have an impact on law-abiding citizens today.