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svp [43]
2 years ago
6

How many half-lives have lapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14

Biology
1 answer:
stich3 [128]2 years ago
8 0

2 half-lives have elapsed to yield  125 atom of the original sample

Half of the amount of the radioisotope present at any given time will undergo  spontaneous disintegration during the succeeding 5730 years. In other words , after 5730 years ,only half of the original amount of 14 c remains in a sample of organic material . Imagine  that you start out with 100 grams of carbon 14 . The half -life is the time it takes for half  of given amount of isotope to decay .

learn more about how many half- lives have lapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N- 14

brainly.com/question/2320811

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Which of these is always part of using the scientific method?
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6 0
3 years ago
The rate at which the concentration of a drug in the bloodstream decreases is proportional to the concentration at any time t. I
Westkost [7]

Answer:

C(t) = C_oe^{-kt}

Explanation:

From the given information:

At any given time (t), let c(t) represent the concentration of the drug present in bloodstream.

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\dfrac{dC}{dt} decrease proportionally to Concentration C

i.e

\dfrac{dc}{dt} \alpha - C

\dfrac{dc}{dt} = -k C

\dfrac{dc}{c} = -k dt

\int \dfrac{dc}{c} = -k \int dt

㏑(C) = -kt + λ

where,

λ is the integration constant.

Integrating at t = 0, concentration of blood = Co g/mL

C(0) = Co

㏑(C₀) = 0 + λ

λ = ㏑(C₀)

From ㏑(C) = -kt + λ

㏑(C) = -kt + ㏑C₀

㏑(C)  - ㏑C₀ =  -kt

\dfrac{C}{C_o} = e^{-kt}

C(t) = C_oe^{-kt}

∴

The concentration of drug in blood at any time t is:

C(t) = C_oe^{-kt}

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Answer:

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