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Dovator [93]
2 years ago
7

Data collected on the depth of the Mississippi River and the water discharge are given in the table:

Mathematics
1 answer:
AlekseyPX2 years ago
4 0

Answer:

C. 0.81; The least-squares regression line, given by ŷ = −126.08 + 122.67x, is a good fit to the data.

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Please help asap!!!!!!!!!!!
Aleksandr-060686 [28]

Answer:

ITS C THE ANSWER IS C

Step-by-step explanation:

5 0
2 years ago
What is 6 1/3 - 4 2/3 = ?
kenny6666 [7]

Answer:

3 1/4 + 2 1/3 = 67 / 12 = 57 1/2

Step-by-step explanation:

Conversion a mixed number to a improper fraction: 3 1/4 = 3 · 4 + 1

4

= 13

4

Conversion a mixed number to a improper fraction: 2 1/3 = 2 · 3 + 1

3

= 7

3

Add: 13

4

+ 7

3

= 13 · 3

4 · 3

+ 7 · 4

3 · 4

= 39

12

+ 28

12

= 39 + 28

12

= 67

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8 0
2 years ago
Read 2 more answers
Can a triangle have sides of length 4,7,11?
Lesechka [4]

Answer:

No because 16+49 does not equal 121.

Step-by-step explanation:

first make 11 the hypotenuse and 4 and 7 side b and A

Use the pythagorean theorem: A^2+B^2=C^2

4^2+7^2=11^2

16+49=121

6 0
3 years ago
I need help asap. anyone?
Charra [1.4K]

Answer:

D

Step-by-step explanation:

Has the correct y-axis and has the graph going the correct way for both functions.

7 0
3 years ago
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I need the answer for this exact question
denis23 [38]

Answer:

y=\frac{7}{2}x-20

Step-by-step explanation:

Let the equation of the line be y-y_1=m(x-x_1) where, 'm' is its slope and (x_1,y_1) is a point on it.

Given:

The equation of a known line is:

y=-\frac{2}{7}x+9

A point on the unknown line is:

(x_1,y_1)=(4,-6)

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is m_1=-\frac{2}{7}

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20

The equation of a line perpendicular to the given line and passing through (4, -6) is y=\frac{7}{2}x-20.

3 0
3 years ago
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