Translate into an algebraic expressions: a x is increased by 50% and decreased by 30% . What is the result?

Mathematics

1 answer:

klemol [59]3 years ago

6 0

Answer:

21x/20 or can be written as x + x/20 .

Step-by-step explanation:

The number is x

step 1

x is increased by 50%

value of 50% of x = 50/100 *x = x/2

New value after this change = x + 50% increase = x + x/2 = 3x/2

Step 2 The value obtained is decreased by 30%

value of 30% newly found number is = 30% of value found in step 1

value of 30% newly found number is = 30/100 * 3x/2 = 9x/20

This value (9x/2) is subtracted from value found in step 1(3x/2) as given that value obtained is decreased by 30%

new value found after 30% decrease = 3x/2 - 9x/20 = (3x*10 -9x)/20

new value found after 30% decrease = (30x-9x)/20 = 21x/20

Thus, the result of x is increased by 50% and decreased by 30% is 21x/20 = x + x/20

You might be interested in

How many solutions does the following equation have? -4(+5) = -4- 20

Rus_ich [418]

Answer:

Step-by-step explanation:

Try looking at it in 2 ways- left side and right side. On the left side we have -4*5, which equals -20. On the right we have -4-20, which equals -24. so then when we add it all together (not literally) we get -20=-24. Since -20 and -24 obviously do not equal eachother, there is no solution.

4 0

3 years ago

X^2-4x+c find the value of c

Sonbull [250]

Answer:

$c = 4$