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Makovka662 [10]
3 years ago
13

Find the value of 9!/(9-2)!. a. 72 b. 36 c. 504 d. 63

Mathematics
2 answers:
emmasim [6.3K]3 years ago
6 0

Answer:

a. 72

Step-by-step explanation:

Factorial (!) means take that number and multiply by all the numbers below it to 1

9! = 9*8*7*6*5*4*3*2*1

(9-2)! = 7! = 7*6*5*4*3*2*1

9*8*7*6*5*4*3*2*1

------------------------------

7*6*5*4*3*2*1

Canceling common factors

9*8

------------------------------

1

72

joja [24]3 years ago
3 0

Answer:

a. 72

Step-by-step explanation:

9!/(9-2)!

= 9 x 8 x 7! / 7!

= 9 x 8

= 72

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16x² − 1  = (4x − 1)(4x + 1) ;  16x² − 4  = 4(2x + 1)(2x − 1); 4x² − 1  = (2x + 1)(2x − 1) ;

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4x² − 9 is also the difference of squares.  The square root of 4x² is 2x and the square root of 9 is 3; this gives us (2x-3)(2x+3).

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