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rjkz [21]
2 years ago
8

Order of operations 8x18/4+15

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
6 0

Answer:

8×18=144

4±15=19

144÷19

7.579 answer

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A mystery element has 18 protons. Which one of the following statements is true about the element?
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Answer:

My guess would be B

Step-by-step explanation:

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310=-6.2f<br> f=??? so confused
Mariulka [41]
F=-50 as multiplying it by -6.2 would give you a positive 310
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Can someone please help me? :(
Sholpan [36]
The answer is attached, hope this helps!

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Find the exact value for x leaving your answer as a surd with a rational denominator where appropriate :
lesya [120]

Answer:

x = 10\sqrt{3}

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin60° = \frac{\sqrt{3} }{2} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{x}{20} = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 20\sqrt{3} ( divide both sides by 2 )

x = 10\sqrt{3}

3 0
3 years ago
Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra
Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize x^2-\frac13 as yet another difference of squares:

x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)

And if you're working over the field of complex numbers, you can go even further. For instance,

x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)

But I think you'd be fine stopping at the first result,

x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}

6 0
3 years ago
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