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IrinaVladis [17]
2 years ago
12

Hey can you please help me posted picture of the question

Mathematics
1 answer:
Andrews [41]2 years ago
4 0
If we observe the graph it crosses x-axis at the following points:
1) x = - 2
2) x = - 5

This means, x+ 2 and x + 5 are the factors of the polynomial. A polynomial can be expressed as the product of its factors. So we can express the given polynomial as (x + 2)(x + 5)

Thus the answer to above question is option C
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Use the following information for problems 1 – 3. Suppose you sign a contract for an annual salary of $50,000 with a guaranteed
erik [133]

Initial salary =  $50,000 .

Rate of raise = 5% each year.

Therefore, each next year salary would be 105% that is 1.05 times.

5% of 50,000 = 0.05 × 50000 = 2500.

Therefore raise is $2500 each year.

According to geometric sequence first term 50000 and common ratio 1.05.

Applying geometric sequence formula

a_n = ar^{n-1}

1) a_n = 50000(1.05)^{n-1}

2) In order to find salary in 5 years we need to plug n=5, we get

a_5 = 50000(1.05)^{5-1}= 50000(1.05)^4

= 50000(1.21550625)

<h3>=$60775.3125.</h3>

3) In order to find the total salary in 10 years we need to apply sum of 10 terms formula of a geometric sequence.

S_n = \frac{a(1-r^n}{1-r}

Plugging n=10, a = 50000 and r= 1.05.

S_10 = \frac{50000(1-(1.05)^{10}}{1-1.05}

S_10 = \frac{50000(0.050)^{10}}{0.05}

= 628894.62678.

<h3>Therefore , you will have earned $ 628894.62678 in total salary by the end of your 10th year.</h3>



7 0
3 years ago
In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was 43.76 with standard deviati
klemol [59]

Answer:

Between 38.42 and 49.1.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 43.76, standard deviation of 2.67.

Between what two values will approximately 95% of the amounts be?

By the Empirical Rule, within 2 standard deviations of the mean. So

43.76 - 2*2.67 = 38.42

43.76 + 2*2.67 = 49.1

Between 38.42 and 49.1.

8 0
2 years ago
PLEASE HELP ME ANSWER THIS FAST
Alenkasestr [34]

Answer:

65 square yards

Step-by-step explanation:

5x5=25

5x4=20

5x4=20

20+20+25= 65

7 0
1 year ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
2 years ago
Which value of c will make the equation true?
sweet-ann [11.9K]

Answer:

A

Step-by-step explanation:

44 - 15 =29

3 0
3 years ago
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