Answer:
SQUARE
Step-by-step explanation:
If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).
Find the following MN, NP, PQ and MQ
Using the formula for calculating the distance between two points
MN = √(6-0)²+(0-4)²
MN = √6²+4²
MN = √36+16
MN = √52
MN = 2√13
NP = √(0-6)²+(-4-0)²
NP = √6²+4²
NP = √36+16
NP = √52
NP = 2√13
PQ = √(-6-0)²+(0-(-4))²
PQ = √6²+4²
PQ = √36+16
PQ = √52
PQ = 2√13
MQ = √(-6-0)²+(0-4)²
MQ = √6²+4²
MQ = √36+16
MQ= √52
MQ = 2√13
Since the length of all the sides are equal, hence the shape is a SQUARE
Answer:
155.7
Step-by-step explanation:
Use what you know.
Segment AC is 130 ft
Segment CD is 70ft
If you use the Pythagorean Theorem, in this case being = +
To find segment CE, you would do r-70
So, = +
= 16,900 + -140r + 4900
Add the -140r to the left side and then get rid of the two . Then Add 16,900 and 4900 together
You'll end up with 140r = 21,800
Divide 140 on each side.
Your final answer will be 155.7 (rounded to the nearest tenth)
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3^8=6,561
6,561 •3=19,683
The highest altitude of an altocumulus cloud is 19,683 feet.
