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ale4655 [162]
3 years ago
11

If x^3+2x^2y-4y=7, then when x=1, dy/dx=

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

dy/dx when x = 1 is (4y + 3) / 2.

Step-by-step explanation:

x^3 + 2x^2y - 4y=7

Using implicit differentiation:

3x^2 + 4xy + 2x^2.dy/dx - 4 dy/dx = 0

2x^2.dy/dx - 4dy/dx = -3x^2 - 4xy

dy/dx =  (-3x^2 - 4xy ) / (2x^2 - 4)

When x = 1:

dy/dx =  (-3 - 4y) / -2  

= -1(4y + 3) / -2

(4y + 3)/ 2 (answer).

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5b= -G+ 1/5 UA Solve for a:
enot [183]

Answer:

switch sides

-g+2/5UA=5b

add g to both sides

-g+1/5UA+g=5b+g

simplify

1/5UA=5b+g

multiply both side by 5

5×1/5UA=5×5b+g

simplify

AU=25b+5g

divide both sides by U

AU/U=25b/u+5g/u =U/U=0

simplify

A=25b+5g/U

8 0
3 years ago
Stanley makes paper constellations. The following data points represent how many stars were in each
____ [38]

Answer:

Check Explanation and the attached image.

Step-by-step explanation:

The histogram of the set of data presented is presented in the attached image to.this solution

The histogram represents data by indicating the frequency of distribution on the y-axis and the sets of variables indicated on the x-axis.

With the constellations named numbers 0 to 6, the frequency of each constellation, that is, the number of stars in each constellation corresponds to the height of the bar representing each constellation.

Hope this Helps!!!

5 0
3 years ago
Help me solve this please. I don't know the formula for this.​
den301095 [7]

Answer

48,000

Step-by-step explanation:

base(x)

1,200(40)

8 0
3 years ago
Which is a better buy?<br><br> 22 vitamins for $2 or 40 vitamins for $4
fomenos

Answer:

i would say 40 for 4$

Step-by-step explanation:

bc ur getting double amount for 2$ and it will last longer

5 0
2 years ago
Read 2 more answers
“ write all your answers with a positive exponent so your answer will be in the form of x^# or 1/(x^#)
gayaneshka [121]

Answer:

Step-by-step explanation:

5). \frac{1}{x^{-9}} = \frac{1}{\frac{1}{x^9} }

     = x^{9}

6). \frac{1}{x^{-2}}=\frac{1}{\frac{1}{x^2} }

      = x²

7). x^{-6}=\frac{1}{x^6}

8). \frac{1}{x^{-7}}=\frac{1}{\frac{1}{x^7} }

           = x^{7}

9). x^{-8}=\frac{1}{x^8}

10). \frac{1}{x^{-3}} = \frac{1}{\frac{1}{x^{3}}}

            = x³

7 0
2 years ago
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