Answer:
(-4/3), 0.4, 0.8, √2, √11
Step-by-step explanation:
√11=3.316624790355399849114932736670686683927088545589353597058
0.4
(-4/3) = -1.33333333333333333333333333333333333333333333333333333333
0.8
√2=1.414213562373095048801688724209698078569671875376948073176
Thus :
(-4/3)
0.4
0.8
√2
√11
Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Answer:1197.421
Step-by-step explanation:
The current cancels doesnt it? so it would be (68*2)mi/5.667hr