All categories

4 years ago

Is 70 thousand in standard form or word?Explain..

Mathematics

1 answer:

CaHeK987 [17]4 years ago

6 0

70 thousand is in word form

You might be interested in

Graph the linear equation. Find three points that solve the equation, then plot on the graph.

Illusion [34]

Answers:

Three points that solve the equation: $(1, \frac{19}{4} ) , (2, 5), (3, \frac{21}{4} )$

The graph is shown in the attached pictures.

NOTE: The first picture is the graph of the equation along with the plotted points, and the second one shows the work for those three points.

Step-by-step explanation:

1. To graph this equation, an easier way to do it would be to convert to slope-intercept form so we can graph knowing the y-intercept and the slope. Do this by isolating the y on the left side like so:

$x-4y=-18\\-4y = -x -18\\y = \frac{-x}{-4} -\frac{18}{-4} \\y = \frac{1}{4} x + \frac{9}{2}$

Remember that slope-intercept form is in y = mx + b format, and that m is the slope and b is the y-intercept. With this information, we know that (0, $\frac{9}{2}$ ) is the y-intercept and $\frac{1}{4}$ is the slope of this equation. We can plot the point (0, $\frac{9}{2}$ ) on the graph, and then use the slope of $\frac{1}{4}$ from there to graph other points and form a line. (When I graphed the line, I didn't include these "other points" so it wasn't confusing to locate which points were the three solutions listed.)

2. Points that solve an equation - or solutions - are also points that the line of the equation intersects. So, what we can do is form a table, plug in some x values into the equation, and solve for a y-value. The x and y values will form a point that is on the graph, thus they are solutions. (Please look at the second picture for work and clarification.) After identifying these points, just plot them on the graph and label them (as shown in the first picture).

8 0

3 years ago

Find an equation of the plane that passes through the points p, q, and r. p(7, 2, 1), q(6, 3, 0), r(0, 0, 0)

Alona [7]

Answer:

x - 2y - 3z = 0

Step-by-step explanation:

The cross product of vectors rp and rq will give a vector that is normal to the plane:

... rp × rq = (-3, 6, 9)

Dividing this by -3 (to reduce it and make the x-coefficient positive) gives a normal vector to the plane of (1, -2, -3). Usint point r as a point on the plane, we find the constant in the formula to be zero. Hence, your equation can be written ...

... x -2y -3z = 0

3 0

4 years ago

2m+2p=16, what does p equal in terms of m

dalvyx [7]

Answer:

m=8-p

Step-by-step explanation:

8 0

3 years ago

The equation of function is y=4x+5 what is the value of y when x=3?

KIM [24]

Answer:

Step-by-step explanation:

y=4(3)+5

y=12+5

y=17

7 0

3 years ago

Read 2 more answers

can someone please help and explain to me on how to do this geometry question please?! Thank youuuuu!!! ❤

qaws [65]

There are 13 angles.
We know that $m\angle4=112$ and $m\angle12=105$ (11 angles)

1.

$m\angle2+m\angle3+m\angle4=180\qquad\qquad\text{linear angles}\\\\m\angle3+m\angle3+m\angle4=180\qquad\qquad m\angle2=m\angle3\\\\2m\angle3+m\angle4=180\\\\2m\angle3+112=180\\\\2m\angle3=180-112\\\\2m\angle3=68\quad|:2\\\\\boxed{m\angle3=34=m\angle2}$

(9 angles)

2.

$m\angle3+m\angle12+m\angle11=180\qquad\qquad\text{triangle}\\\\34+105+m\angle11=180\\\\139+m\angle11=180\\\\m\angle11=180-139\\\\\boxed{m\angle11=41}$

(8 angles)

3.

$m\angle12+m\angle13=180\qquad\qquad\text{linear angles}\\\\105+m\angle13=180\\\\m\angle13=180-105\\\\\boxed{m\angle 13=75}$

(7 angles)

4.

$m\angle1+m\angle2+m\angle13=180\qquad\qquad\text{triangle}\\\\m\angle1+34+75=180\\\\m\angle1+109=180\\\\m\angle1=180-109\\\\\boxed{m\angle1=71}$

(6 angles)

5.

$m\angle9=m\angle11\qquad\qquad\text{vertical angles}\\\\\boxed{m\angle9=41}$

(5 angles)

6.

$m\angle10+m\angle11=180\qquad\qquad\text{linear angles}\\\\m\angle10+41=180\\\\m\angle10=180-41\\\\\boxed{m\angle10=139}$

(4 angles)

7. $a||b\text{ and } c||d$ so we have a parallelogram.

$m\angle4+m\angle5=180\qquad\text{consecutive angles are supplementary}\\\\112+m\angle5=180\\\\m\angle5=180-112\\\\\boxed{m\angle5=68}$

(3 angles)

$m\angle8=m\angle5\qquad\qquad\text{opposite angels are congruent}\\\\\boxed{m\angle8=68}$

(2 angles)

8.

$m\angle7+m\angle8+m\angle9=180\qquad\qquad\text{triangle}\\\\m\angle7+68+41=180\\\\m\angle7+109=180\\\\m\angle7=180-109\\\\\boxed{m\angle7=71}$

(1 angle)

9.

$m\angle1+m\angle5+m\angle6=180\qquad\qquad\text{triangle}\\\\71+68+m\angle6=180\\\\139+m\angle6=180\\\\m\angle6=180-139\\\\\boxed{m\angle6=41}$

6 0

3 years ago