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klio [65]
3 years ago
12

stans cookie recipe makes 24 cookies and calls for exactly 384 sprinkles. he is wondering how many sprinkles (p) he will need to

make 60 cookies. he assumes each cookie will have the same number of sprinkles. how many sprinkles does stan need to make 60 cookies
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

960 sprinkles

Step-by-step explanation:

If 24 cookies call for EXACTLY 384 sprinkles, then 16 sprinkles fit on each cookie. 384/24 = 16

If 16 sprinkles fit on each cookie, 16 cookies on 60 cookies would be 960.

60 x 16 = 960

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Can someone please help me with this problem
DerKrebs [107]

For Erin, the graph shows 10 pounds of sugar are used for every 30 cups of tea.

For Lucia, we can let x=3 and we find 3 pounds of sugar are used for 10·3 = 30 cups of tea.

For the same number of cups of tea (30), Erin uses 10 pounds of sugar and Lucia uses 3 pounds of sugar.

Erin uses sugar at a higher rate.

6 0
3 years ago
X−3(5x−6)=3−10x What is x, and how do you find x?
Fudgin [204]

Answer:

x=3or-1

Step-by-step explanation:

x-3 (5x-6)=3-10x

5x^2-15x-6x+18=3-10x

collect like terms

5x^2+18-3=15x+6x-10x

5x^2+15=11x

5x^2-11x+15=0

factorise

(x-3) (5x+5) =0

...... x=3 or -1

pls like if helpful nd rank me as most helpful ans

7 0
4 years ago
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
1 + 2k = 5k + 7 I got k=2 don't know if it's the right answer ?
DochEvi [55]
You are close, but it is not the correct answer.

1 + 2k = 5k + 7

First, since we are trying to get the variable by itself, we need to move all things to one side. Let's subtract 1 from each side. 
2k = 5k + 7 - 1

Second, we can now subtract (7 - 1) to get 6. Let's add that into our problem and then subtract 5 from each side, still trying to get the variable by itself.
2k - 5k = 6

Third, subtract (2k - 5k) to get -3k. Hint the negative symbol now. If the problem were switched the other way, it would still be a positive. 
-3k = 6

Fourth, we can now divide each side by -3. This results in a fraction and also getting the variable by itself on one side of the problem. Remember the negative sign in front of the fraction since (-3) carried it.
k = - \frac{6}{3}

Fifth, this is our last step. We need to simplify the fraction. Since out fraction is 6/3, which number multiples by 3 to get the answer of 6? The answer is 2, since (3 × 2 = 6). Don't forget the negative!
k = -2

Answer: \fbox {k = -2}
4 0
4 years ago
Oranges cost $0.35 per pound and bananas cost $1.41 per
Anna [14]
She paid $5.669. Rounded to the nearest hundredth, $5.67. Rounded to the nearest whole number, $6.
8 0
3 years ago
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