13. If AC = 16, DE = 8 and BE = 6, find AE. Please show all work
1 answer:
Answer:
AE = 4
Step-by-step explanation:
Use the formula
AE*EC = DE*EB
Since we don't know AE or EC, let AE = x and then EC will = 16 - x. The formula then becomes
x(16 - x) = 8(6)
Getting everything on one side and setting it equal to 0 will allow us to factor for x:
Factoring that gives you that
x = 4 and x = 12. That means that one of those sements has a length of 4 and the other has a length of 12. AE is shorter so it's 4 and EC = 12
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Answer:
The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Step-by-step explanation:
Given : The position of an object along a vertical line is given by , where s is measured in feet and t is measured in seconds.
To find : What is the maximum velocity of the object in the time interval [0, 4]?
Solution :
The velocity is rate of change of distance w.r.t time.
Distance in terms of t is given by,
Derivate w.r.t. time,
It is a quadratic function so its maximum is at vertex of the function.
The x point of the function is given by,
Where, a=-3, b=6 and c=7
As 1 lie between interval [0,4]
Substitute t=1 in the function,
Th maximum velocity is 10 ft/s.
Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.