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goldenfox [79]
3 years ago
13

The LCD of 7/10 and 1/4 is 40. true or false?

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0
False. The LCD is 20
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Samantha has chocolate bars and lollipops in the the ratio 4:5. If she has 12 chocolate bars,how many lollipops does she have?
labwork [276]
4 • 3 = 12
5 • 3 = 15
she has 15 lollipops
8 0
3 years ago
Help! i need this done this is worth 50% of my grade-
Colt1911 [192]

Answer:

A

Hope you get it right!:)

8 0
3 years ago
How many solutions does the equation have?
Rus_ich [418]
2(2x+5)=4(x+3)\\2\times2x+2\times5=4\times x+4\times3\\4x+10=4x+12\ \ \ \ |subtract\ 4x\ from\ both\ sides\\10=12-FALSE\\\\therefore,\ answer\ is\ \boxed{C.\ No\ solution}
7 0
3 years ago
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Find all solutions of the equation in the interval [0, 2pi).
natali 33 [55]

Answer:

Step-by-step explanation:

Begin by squaring both sides to get rid of the radical. Doing that gives you:

sin^2x=1-cosx

Now use the Pythagorean identity that says

sin^2x =1-cos^2x and make the replacement:

1-cos^2x=1-cosx. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:

1-cos^2x+cosx-1=0 and then simplify to

cosx-cos^2x=0

Factor out the common cos(x) to get

cosx(1-cosx)=0 and there you have your 2 trig equations:

cos(x) = 0 and 1 - cos(x) = 0

The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

x=\frac{\pi }{2},\frac{3\pi}{2}

The second equation simplifies to

cos(x) = 1

Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.

So, in the end, your 3 solutions are

x=\frac{\pi}{2},\pi,\frac{3\pi}{2}

8 0
3 years ago
Factor this expression completely. 9x (squared) -16​
notsponge [240]
Soln,

here

9 {x}^{2} - 16

= ( {3x)}^{2} - {4}^{2}

= (3x + 4)(3x - 4)
I hope this was helpful.
3 0
3 years ago
Read 2 more answers
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