Ah so your confused? I got you fam let me explain. So it would be best to start in the middle then graph the coordinates, move those coordinates 6 right then 5 up for the first one. Then do the same thing for the other but move them 8 left and down once.
Answer:
Let first no. be x
Therefore,
2nd no. is x+1
Third no. is x+2
<em><u>SUM</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>NO</u></em><em><u>.</u></em><em><u>'</u></em><em><u>s</u></em><em><u>=</u></em><em><u>x</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>2</u></em>
<em><u>S</u></em><em><u>=</u></em><em><u>3x</u></em><em><u>+</u></em><em><u>3</u></em>
<em><u>S</u></em><em><u>=</u></em><em><u>3</u></em><em><u>(</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>)</u></em>
Answer:
The answer to your question is 113.04 in²
Step-by-step explanation:
To solve this problem substitute the values in the formula and simplify.
Data
Area = ?
radius = 6 in
π = 3.14
Formula
Area = π x r²
Substitution
Area = (3.14) x (6)²
Simplification
Area = 3.14 x 36
Result
Area = 113.04 in²
I Am Going Ask My teacher. I just screenshot it.
The triangle inequality applies.
In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.
In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.
The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}