Ask question

Ask question

All categories

3 years ago

15

Sal bought a house for $78,524.60. Twelve years later he sold the house for 2 3/4 times as much. What was the sale price of the

house?

1 answer:

Oksi-84 [34.3K]3 years ago

8 0

215,415 sorry if my answer might be incorrect

You might be interested in

Please show me step by step how to solve this problem 3(-8+4v)=8v ?

Nadusha1986 [10]

So we know that:
3(-8 + 4v) = 8v
To find v, first simplify the left hand side:
-24 + 12v = 8v
Then group the "v's" over to the right:
-24 = -4v
-6 = -v
So v = 6

Hope this helped

8 0

3 years ago

PLZZZ HELPPPPPPPPPPP

Oliga [24]

Answer:

Step-by-step explanation:

29 5x+8+x+4=90

6x=78

x=13

30 3x-7+11x-1=90

14x=98

x=7

31 3x+x+8=180

4x=172

x=43

32 6x-1+5x-17=180

11x=198

x=18

7 0

2 years ago

Pls help ASAP this is due in 1 hour and i can't figure it out! HELPPP

Paul [167]

the area of the surface of this design is 31 in long

4 0

1 year ago

Read 2 more answers

Estimate the sum of 23 and 71

Natali [406]

Estimation:

23 --> rounded to 20
71 --> rounded to 70
70 + 20 = 90. I rounded both numbers down so the exact sum must be only a little greater than my estimate.

8 0

3 years ago

Read 2 more answers

Charles has 2 2/3 ounces of seeds. He needs 4 4/5 ounces in order to complete the garden. How much more seeds he need?

yawa3891 [41]

Answer:

Charles need $3\frac{1}{5}$ more ounces of seeds.

Step-by-step explanation:

Given that:

Quantity of seeds Charles has = $2\frac{2}{3}$ = $\frac{8}{3}$ ounces

Quantity of seeds Charles need = $4\frac{4}{5} = \frac{24}{5}$ ounces

Let,

x be the number of remaining seeds Charles need.

x = Seeds needed - Seeds Charles already have

x = $\frac{24}{5}-\frac{8}{3}$

x = $\frac{72-24}{15}$

x = $\frac{48}{15}$

x = $\frac{16}{5}$

x = $3\frac{1}{5}$ ounces

Hence,

Charles need $3\frac{1}{5}$ more ounces of seeds.

5 0

2 years ago