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Lena [83]
3 years ago
12

Phalicia is a senior at North HS and wants to begin saving for college. She's trying to choose between two savings account optio

ns.
Option 1: Phalicia deposits $300 and deposits an additional $50 each month.
Option 2: Phalicia deposits $5 and it triples each month.
Which option should she choose
Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

Option 2

Step-by-step explanation:

Let's say that Phalicia opens her savings account one year (12 months) before she goes to college.

With Option 1, she would have saved 300 + 50 * 11 = $850. We do 50 * 11 and not 50 * 12 because she deposits $50 for 11 months, not 12.

With Option 2, she would have saved 5 * 3¹¹ = $885735. Note that we do 3¹¹ and not 3¹² because 5 is being tripled 11 times.

Obviously, she should choose Option 2 because she saves A LOT more money.

Additionally, we can notice that Option 1 is an example of an arithmetic sequence whereas Option 2 is an example of a geometric sequence. Their explicit formulas would be aₙ = 50n + 250 and aₙ = 5 * 3⁽ⁿ⁻¹⁾ respectively.

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P(x) = x + 1x² – 34x + 343<br> d(x)= x + 9
Feliz [49]

Answer:

x=\frac{9}{d-1},\:P=\frac{-297d+378}{\left(d-1\right)^2}+343

Step-by-step explanation:

Let us start by isolating x for dx = x + 9.

dx - x = x + 9 - x > dx - x = 9.

Factor out the common term of x > x(d - 1) = 9.

Now divide both sides by d - 1 > \frac{x\left(d-1\right)}{d-1}=\frac{9}{d-1};\quad \:d\ne \:1. Go ahead and simplify.

x=\frac{9}{d-1};\quad \:d\ne \:1.

Now, \mathrm{For\:}P=x+1x^2-34x+343, \mathrm{Subsititute\:}x=\frac{9}{d-1}.

P=\frac{9}{d-1}+1\cdot \left(\frac{9}{d-1}\right)^2-34\cdot \frac{9}{d-1}+343.

Group the like terms... 1\cdot \left(\frac{9}{d-1}\right)^2+\frac{9}{d-1}-34\cdot \frac{9}{d-1}+343.

\mathrm{Add\:similar\:elements:}\:\frac{9}{d-1}-34\cdot \frac{9}{d-1}=-33\cdot \frac{9}{d-1} > 1\cdot \left(\frac{9}{d-1}\right)^2-33\cdot \frac{9}{d-1}+343.

Now for 1\cdot \left(\frac{9}{d-1}\right)^2 > \mathrm{Apply\:exponent\:rule}: \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} > \frac{9^2}{\left(d-1\right)^2} = 1\cdot \frac{9^2}{\left(d-1\right)^2}.

\mathrm{Multiply:}\:1\cdot \frac{9^2}{\left(d-1\right)^2}=\frac{9^2}{\left(d-1\right)^2}.

Now for 33\cdot \frac{9}{d-1} > \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} > \frac{9\cdot \:33}{d-1} > \frac{297}{d-1}.

Thus we then get \frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}+343.

Now we want to combine fractions. \frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}.

\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}\left(d-1\right)^2\mathrm{\:or\:}d-1 > This\: is \:the\:LCM > \left(d-1\right)^2

\mathrm{For}\:\frac{297}{d-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:d-1 > \frac{297}{d-1}=\frac{297\left(d-1\right)}{\left(d-1\right)\left(d-1\right)}=\frac{297\left(d-1\right)}{\left(d-1\right)^2}

\frac{9^2}{\left(d-1\right)^2}-\frac{297\left(d-1\right)}{\left(d-1\right)^2} > \mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}> \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\frac{9^2-297\left(d-1\right)}{\left(d-1\right)^2} > 9^2=81 > \frac{81-297\left(d-1\right)}{\left(d-1\right)^2}.

Expand 81-297\left(d-1\right) > -297\left(d-1\right) > \mathrm{Apply\:the\:distributive\:law}: \:a\left(b-c\right)=ab-ac.

-297d-\left(-297\right)\cdot \:1 > \mathrm{Apply\:minus-plus\:rules} > -\left(-a\right)=a > -297d+297\cdot \:1.

\mathrm{Multiply\:the\:numbers:}\:297\cdot \:1=297 > -297d+297 > 81-297d+297 > \mathrm{Add\:the\:numbers:}\:81+297=378 > -297d+378 > \frac{-297d+378}{\left(d-1\right)^2}

Therefore P=\frac{-297d+378}{\left(d-1\right)^2}+343.

Hope this helps!

5 0
3 years ago
The diagram shows the diffrence between my home h and two towns
katrin2010 [14]

Answer:

  • from home to town A :

V = D/t = 10 / 20 = 0.5 mile per min

  • from home to town B :

V = D/t = 20/30 = (2/3) mile per min

  • From town A to town B :

V = D/t = (10+20)/ 50 = (3/5) mile per min

6 0
3 years ago
Read 2 more answers
How to solve<br> -22-x=5+6x+9
nadya68 [22]
  -22 - x = 5 + 6x + 9   Combine like terms (5 and 9)
  -22 - x = 14 + 6x        Subtract 6x from both sides
-22 - 7x = 14                Add 22 to both sides
        -7x = 36               Divide both sides by -7
           x = 5\frac{1}{7}
6 0
3 years ago
(This is more like science!) the question is : According to the diagram below in what direction will the motion of the book go?
Elis [28]

Answer:

a to the top left hope this help

7 0
3 years ago
Y=99.99+23.75(x-1) as a Y=ax+b equation
Hatshy [7]

Answer:

y = 23.75x  + 76.24

Step-by-step explanation:

We want to rewrite

y = 99.99 + 23.75(x - 1)

in the form

y = ax + b

We expand to get:

y = 99.99 + 23.75x - 23.75

Regroup similar terms:

y = 23.75x - 23.75 + 99.99

Simplify:

y = 23.75x  + 76.24

This is now of the form

y = ax + b

where a=23.75 and b=76.24

6 0
3 years ago
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