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sashaice [31]
3 years ago
6

Gcmf of 25x²y³+55xy³​

Mathematics
2 answers:
astraxan [27]3 years ago
5 0

Answer: the answer is 5xy^3

solmaris [256]3 years ago
4 0
What is rbisssssssssssss
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Looking for an answer to a. please
Paladinen [302]
It's a cube so x should also equal 6
4 0
3 years ago
The exact value of cos 13pi/8 is
Naily [24]

Answer:

answer is : Cos(13pi/8) = 0.3826  

Step-by-step explanation:

We have, Cos (13pi/8)

Since 13pi/8 can be shown as 3pi/2 < 13pi/8 < 2pi

Hence 13pi/8 lies on fourth quadrant.

In fourth quadrant cosine will be positive.

Cos (13pi/8) = cos(3pi/2 + pi/8)

applying formula cos(A+B) = cos A cosB - sinAsinB

i.e Cos(3pi/2 + pi/8) = cos(3pi/2)cos(pi/8) - sin(3pi/2)sin(pi/8)

∵ Remember cos(3pi/2) =0 , sin(3pi/2) = -1

     Cos(3pi/2 + pi/8) = 0 cos(pi/8) - (-1)sin(pi/8)

     Cos(3pi/2 + pi/8) = 0  + 0.3826

      Cos(3pi/2 + pi/8) = 0.3826

Hence we got Cos(13pi/8) = 0.3826                          

6 0
3 years ago
Read 2 more answers
some poeple where asked which there favourite school subject was, from a choiceof maths, english and science. how many people in
Sedaia [141]

Answer:

IS THERE MORE TO THE PROBLEM? NOT ENOUGH INFORMATION IS GIVEN

Step-by-step explanation:

5 0
3 years ago
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
The total charge that a tow truck driver charges to tow a vehicle can be represented by the graph below.
weeeeeb [17]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
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