(4xy-2y^2)+2y
4-2=2....x will remain y^1-y^2=y^-1
2xy^-1+2y
answer=2x+2y
        
             
        
        
        
Here is your answer 
Money saved on each successive day is-
$3, &5, $7....
Clearly it forms an AP,
where 
a1= 3 
common difference, d= 2
n=20 
So,
using formula
Tn= a1+(n-1)d
T20= 3+(20-1)2
= 3+ 19×2
= 3+ 38
=41
So, money saved on August 20= $41
Sum of money saved upto August 20 = 
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440
HOPE IT IS USEFUL
        
                    
             
        
        
        
It would be 6.5. The 5 after the decimal would stay the same since the number after it isn't greater than 5
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
From the problem statement, we can setup the following equation:

where  is the number of months that Rachel has saved up money.
 is the number of months that Rachel has saved up money.
Dividing both sides by 35, we get the answer:
