Answer:
x^2 -x -2 = (x -2)(x +1)
Step-by-step explanation:
To factor x^2 -x -2, you look for factors of -2 that have a sum of -1:
-2 = (-1)(2) = (1)(-2) . . . . . the latter pair has a sum of -1
Then these are the constants in the binomial factors:
x^2 -x -2 = (x +1)(x -2)
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<em>Comment on the question</em>
The fact that x^2 +3x -4 is modeled with algebra tiles seems to be irrelevant to the question that is actually asked.
The missing value is 6 so 2/5 = 6/15
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
Answer:
Step-by-step explanation:
If these 3 points are collinear, then we can find the slope of the linear function using any 2 of those points. Suppose we use (-4, 3) and (0, 1):
As we move from (-4, 3) to (0, 1), x increases by 4 and y decreases by 2. Hence, the slope of this lilne is m = rise/run = -2/4, or m = -1/2.
Using the slope-intercept formula y = mx + b and replacing y with 1, x with 0 and m with -1/2, we get:
1 = (-1/2)(0) + b, or b = 1. Then the desired equation is y = f(x) = (-1/2)x + 1
it would take him 32 minutes. You could use divisoin and multiplecation to figure it out
