Answer:
the question is not understandable
Answer:
A. 0.22
B. 0.18
C. 0.25
D. 0.244
Step-by-step explanation:
S = {51 to 100} = 50
The sample space S contains values from 51 to 100 which is a total of 50 different values.
A.
Probability of A (lies between the values of 90 to 100 = 11).
11/50 = 0.22
B.
For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.
9/50 = 0.18
C.
For student to get c, (70 to 79) a total of 10 values: 10/50 = 0.20
P(student did not get C) = 1-0.20 = 0.80
To get B, ( 80 to 89)
10/50 = 0.20
Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25
D.
Probability of passing lies between 60 to 100 = 41 scores
41/50 = 0.82
Probability of student who passed having a B = 0.20/0.82 = 0.244
Answer:
20/3
Step-by-step explanation:
The grade of her sci test was 61. First I add 37 to 85, the sum being 122. Then if you divide it in half, you get the quotien and final answer of 61
Answer:
A) Red and Blue Bulbs
B) 262 lightbulbs.
Step-by-step explanation:
A) red and blue = 85+52=137
Yellow and green = 76+49=125
Answer to A is Red and Blue bulbs
Bulbs in all: We already know from A that there are 137 and 125 so 137+125 is 262.
Hope this helps plz hit the crown :D
