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Novosadov [1.4K]
4 years ago
12

What is the solution to the equation 1/3(x-2)=1/5(x+54)+2

Mathematics
2 answers:
Marta_Voda [28]4 years ago
7 0
0.13 I’m not sure tho
Dennis_Churaev [7]4 years ago
5 0

Answer:

x=101

Step-by-step explanation:

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Help me plssssssssssssss
siniylev [52]

Answer:

yes

Step-by-step explanation:

why do you need this silly boy

6 0
3 years ago
Animal shelter house ratio catch a dog that is 9:7. If the shelter only as his dogs and cats what is the ratio of dogs total ani
Molodets [167]

Answer:

The ratio of dogs to animals  \frac{9}{16}.

Step-by-step explanation:

If the shelter captures 9 dogs they also catch 7 cats.

So,

the total number of Animals = Total number of Dogs + Total number of Cats

                                                = 9+7

                                                 =16

Therefore,

The ratio of dogs to animals    = Number of Dogs / Total number of animals

                                                   = \frac{9}{16}

5 0
4 years ago
Read 2 more answers
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
4 years ago
Answer this for 15 points
djyliett [7]

Answer:

A.

Step-by-step explanation:

y = mx + b

y = -2/3 x + b

(x, y) = (3, 0)

0 = -2/3 (3) + b

0 = -2 + b

b = 2

y = -2/3 x + 2

Answer: A.

8 0
3 years ago
Read 2 more answers
F(x) = 3x^4 + 19x^3 + 69x^2 + 99x + 26
bagirrra123 [75]

Answer:

sorry

Step-by-step explanation:

3 0
3 years ago
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