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hichkok12 [17]
3 years ago
7

I need help with tthis

Mathematics
2 answers:
algol [13]3 years ago
8 0
Yeah it would be the first and second
Tanzania [10]3 years ago
4 0
It is the first, second, and the last answers
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A study of recent records of car accidents revealed that average proportion of drivers who were distracted by their phones at th
aksik [14]

Answer:

At least 547 records need to be studied.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

And the margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so z = 1.96.

In this problem, we have that:

M = 0.04, p = 0.35

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.35*0.65}{n}}

0.04\sqrt{n} = 0.93486

\sqrt{n} = 23.37

n = 546.2275

At least 547 records need to be studied.

6 0
3 years ago
Points (4, 3) and (0, 6) Mid point
V125BC [204]

Answer:

(3.5,3)

Step-by-step explanation:

Midpoint= (x¹+x²/2, y¹+y²/2)

x¹=4

x²=3

y¹=0

y²=6

Put your values into the formula

(4+3/2,0+6/2)

(7/2, 6/2)

(3.5,3)

5 0
2 years ago
Which is equal to 100%?<br> O A 0.001<br> B.<br> 100<br> O c. 0.1<br> 10<br> 10<br><br> Need ASAP
Phoenix [80]

Answer:

100% equals to 1 because 75% = 0.75 so then just add 25% = 0.25 so 0.25+0.75=1

Step-by-step explanation:

7 0
3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
Friday night's football game was attended by 420 students. This is about 60 % of the school's population. What
Rainbow [258]

Answer:

the answer is 672

Step-by-step explanation:

420 × 60% = 252

420 + 252=672

625 is the total number of learners

3 0
3 years ago
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