All categories

2 years ago

ABC is an isosceles AB= 3x-4 and BC= 5x-10 what is AB?

Mathematics

2 answers:

Kitty [74]2 years ago

8 0

AB = 5
3x-4=5x-10
-3. -3
-4 = 2x -10
+10. +10
6 = 2x (divide by 2 on both sides)
X = 3

AB = 3x-4
3(3)-4 ( substitute for x)
9 - 4
= 5

kakasveta [241]2 years ago

3 0

3x-4=5x-10
Subtract 3x from both sides
-4=2x-10
Add 10 to both sides
6= 2x
X= 3
3 times 3-4
AB=5

You might be interested in

When your classmates began their hike, they

Ede4ka [16]

Answer:

% increase = 200%

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need to find the volume of the cylinder

masha68 [24]

Answer:

depends on what kinda cylinder your starting to find a answer to

3 0

3 years ago

Solve pls brainlies

MrRa [10]

Answer:

2) 11

3) 21

4) 7

Step-by-step explanation:

2) (-6) -(-17) = 17 - 6 = 11

3) 19 - (-2) = 19 + 2 = 21

4) (-13) + 20 = 20 - 13 = 7

6 0

2 years ago

The weight of a box varies directly as the volume of the box . If a 138 - pound box has a volume of 23 gallons , what is the wei

Marizza181 [45]

Answer:

150 lb

Step-by-step explanation:

138lb/23 gal = x/25 gal

cross multiply and solve for x

23x = 138·25

x = 3450/23

x = 150 lb

3 0

3 years ago

PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK

Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
∠KLM = 58.24313614°

$\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)$

$\implies \textsf{Arc length MK}=\sf 15.45132428\:units$

6 0

2 years ago