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2 years ago

Find the value of 64 ÷ 2 ∙ 16. 2 32 512

Mathematics

2 answers:

irga5000 [103]2 years ago

6 0

The value of 64 divided by 2 multiplied by 16 is 512

Ostrovityanka [42]2 years ago

3 0

Answer:

$\Huge \boxed{512}$

Step-by-step explanation:

To find the value of 64/2*6, first you have to use the order of operations stands for parenthesis, exponents, multiply, divide, add, & subtract the numbers from left to right. Please Excuse My Dear Aunt Sally!

First, multiply & divide numbers from left to right.

$\displaystyle 64\div2\times16$

$\displaystyle 64\div2=32$

$\displaystyle 32\times16=\boxed{512}$

As a result, the correct answer is C. 512.

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3 years ago

Read 2 more answers

A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin

sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

$P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}$

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$P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}$

$P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625$

$P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625$

$P(X=6)=0.225$

Therefore, The probability that they each win six games is 0.225.

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