Find the value of 64 ÷ 2 ∙ 16. 2 32 512

Mathematics

2 answers:

irga5000 [103]3 years ago

6 0

The value of 64 divided by 2 multiplied by 16 is 512

Ostrovityanka [42]3 years ago

3 0

Answer:

$\Huge \boxed{512}$

Step-by-step explanation:

To find the value of 64/2*6, first you have to use the order of operations stands for parenthesis, exponents, multiply, divide, add, & subtract the numbers from left to right. Please Excuse My Dear Aunt Sally!

First, multiply & divide numbers from left to right.

$\displaystyle 64\div2\times16$

$\displaystyle 64\div2=32$

$\displaystyle 32\times16=\boxed{512}$

As a result, the correct answer is C. 512.

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If -1 and 2 are the two zeros of the polynomial x3-4x2-7x+10 find the third zero

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note that the zeroes should be x = 1 and x = - 2 not x = - 1 and x = 2

the factors are then ( x - 1 ) and (x + 2)

and x³ - 4x² - 7x + 10 = (x - 1 )(x + 2) = x² + x - 2

thus x² + x - 2 is a factor

dividing x³ - 4x² - 7x + 10 by x² + x - 2 gives x - 5

the third zero is x = 5

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The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance b

Dima020 [189]

Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug in the numbers:
${4}^{2} + {3}^{2} = {c}^{2} \\ \\ = 16 + 9 \\ \\ = 25 \\ \\ c = \sqrt{25} = 5$
c is 5.

Same thing with g:
${e}^{2} + {f}^{2} = {g}^{2} \\ \\ {g}^{2} = {4}^{2} + {4}^{2} \\ \\ = 16 + 16 \\ \\ = 32 \\ \\ g = \sqrt{32} = 4 \sqrt{2} = 5.66$
g equals 5.66.