We know the full protractor measures 180 degrees.
We need to know what angle it is on. By looking at it, it looks like it is on 135.
180-135= 45
The angle is 45 <em>degrees.
I hope this helps!
~kaikers</em>
We can compute the integral directly: we have

Then the integral is



You could also take advantage of Stokes' theorem, which says the line integral of a vector field
along a closed curve
is equal to the surface integral of the curl of
over any surface
that has
as its boundary.
In this case, the underlying field is

which has curl

We can parameterize
by

with
and
.
Note that when viewed from above,
has negative orientation (a particle traveling on this path moves in a clockwise direction). Take the normal vector to
to be pointing downward, given by

Then the integral is



Both integrals are kind of tedious to compute, but personally I prefer the latter method. Either way, you end up with a value of
.
600kb in 24 seconds to find out how many kbs per second divide by 24
600/24 is 25kb
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
